1) 3!=6
2) 2!=2
3) 1!=1
4) 0!=1
So to get from 1) to 2), you divide by 3; to get from 2) to 3), you divide by 2, so in order to keep the pattern going, to get from 3) to 4), you divide by 1, yielding 1/1=1.
@Rolies, if a false statement is accepted as true, it implies that any statement whatsoever is true (this is often expressed as "a false statement implies any statement"); therefore, truthiness loses its meaning if we accept 1 != 0 as false, and therefore, ((1 != 0) = false) has no logic value.
Discussion (6)
There exists a field for which this is not true, but it is what the head of my math department called the "stupid field."
I've been looking for a PhD field...
The reason for this is:
1) 3!=6
2) 2!=2
3) 1!=1
4) 0!=1
So to get from 1) to 2), you divide by 3; to get from 2) to 3), you divide by 2, so in order to keep the pattern going, to get from 3) to 4), you divide by 1, yielding 1/1=1.
1! == 1
1! != 0
0! == 1
0 != 1
1 != 0
@Rolies, if a false statement is accepted as true, it implies that any statement whatsoever is true (this is often expressed as "a false statement implies any statement"); therefore, truthiness loses its meaning if we accept 1 != 0 as false, and therefore, ((1 != 0) = false) has no logic value.
Except for extremely large values of 0, yes. :P